使用XPath读取XML文件实例

import java.net.URL;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.XPath;
import org.dom4j.io.SAXReader;

public class XmlParser {
	
	
	@SuppressWarnings("unchecked")
	public Map<String, String> readXml(Map<String, String> beanMap,
			String xmlPath) throws DocumentException {
		SAXReader sax = new SAXReader(); 
		Document doc = null;
		URL xmlUrl = this.getClass().getClassLoader().getResource(xmlPath); //得到类实例--得到加载器--根据路径得到URL
		doc = sax.read(xmlUrl);
		Map<String, String> nsMap = new HashMap<String, String>();
		nsMap.put("ns", "http://servicebeans.qinqing.org/dtds/");
		XPath xsub = doc.createXPath("//ns:beans/ns:bean"); //注意路径，参考
 //http://www.w3school.com.cn/xpath/index.asp   
		xsub.setNamespaceURIs(nsMap); //创建命名空间
		List<Element> beans = xsub.selectNodes(doc);
		synchronized (beanMap) {
			for (Element element : beans) {
				String name = element.attributeValue("name");
				String classpath = element.attributeValue("class");
				beanMap.put(name, classpath);
			}
		}
		return beanMap;
	}